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![]() Enthusiast ![]() ![]() ![]() Joined Aug 18, '04 From St. Louis, Missouri Currently Offline Reputation: 0 (0%) ![]() |
i have a 12v source, (4) 540 ohm resistors, and (5) 3.3v LED's that need ~ 20-25mA each. how do i do this?
EDIT: just did a resistor calculator, and it says the resistors are 560ohm. This post has been edited by rocky2006: Jun 2, 2005 - 5:01 PM -------------------- ![]() |
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Enthusiast ![]() ![]() ![]() ![]() Joined Apr 22, '04 From Rhode Island Currently Offline Reputation: 3 (100%) ![]() |
hmmm i think u should have the - of the first led to the + of the secnod then the 2nd led - to the 3rd led + and so on until u get to the last led and connect the negitive wire from the battery to the - on the led
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