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![]() Enthusiast ![]() ![]() ![]() Joined Aug 18, '04 From St. Louis, Missouri Currently Offline Reputation: 0 (0%) ![]() |
i have a 12v source, (4) 540 ohm resistors, and (5) 3.3v LED's that need ~ 20-25mA each. how do i do this?
EDIT: just did a resistor calculator, and it says the resistors are 560ohm. This post has been edited by rocky2006: Jun 2, 2005 - 5:01 PM -------------------- ![]() |
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![]() Enthusiast ![]() ![]() ![]() Joined Aug 18, '04 From St. Louis, Missouri Currently Offline Reputation: 0 (0%) ![]() |
if anyone else does this in blue, use a 100 ohm resistor and wire the 3 LEDs in series. this gave me about 25mA and turned out a lot better. other LEDs will require a different resistor. i wasnt able to get pics last night, but ill try to get some tonight. these were the LEDs i used in blue:
http://www.fiberopticproducts.com/danise/c...gory=InvertedWB -------------------- ![]() |
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