Jan 28, 2010 - 12:32 AM
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![]() Enthusiast Joined Jan 20, '10 From uk Currently Offline Reputation: 0 (0%) |
Hi to all,
This is all Information I myself have gathered from the MECP Installers Guide book. Alright Here's the Question! I am trying to figure out how much pull on my alternator I am getting from the amp. Here is the formula We use to figure this out I = (Po - n*Po + Po) / V Now I = amperes Po=RMS n=efficiency V=voltage So for me its: I = (3000 - .8*3000 + 3000) / 13.8 So I do this 3000*.8 and i get 2400 3000-2400=600 600+3000 3600/13.8 260.87 This is my amperage draw correct? and if I'm correct for everyone else heres an easier equation for this: I = (2-n)Po/V So for me this would go 1. 2-.8 =1.2 2. 1.2*3000=3600 3. 3600/13.8 And there we go. 260.87!!!!! Now, We must remember that Most Class D Amplifiers have a 80% Efficiency Rating and Most Class A/B Amplifiers have a 60-70% efficiency Rating! -------------------- |
lura345 CAR AUDIO : Determine Your Ampere's Pull Jan 28, 2010 - 12:32 AM
freddy121389 3000rms thats a lot of power for sound system, wha... Jan 30, 2010 - 3:23 AM
Cs91 You would need like 3-4 Batteries too keep up with... Jan 30, 2010 - 10:47 AM
freddy121389 he would need a 2-3 alternators, batteries are a w... Jan 30, 2010 - 7:45 PM
RocketScott He's in the UK so that would be a metric 3000r... Jan 30, 2010 - 8:33 PM
OOBE An ambulance alternator is what people here use fo... Jan 30, 2010 - 10:40 PM![]() ![]() |
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