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Enthusiast ![]() Joined Mar 26, '10 From Bronx, Ny, 10466 Currently Offline Reputation: 3 (100%) ![]() |
Any body have any idea how or what I should use to make a 6volt LED light on a 12volt power supply? I know that if I tap it on directly to the 12volt it will burn but I cant figure out how to make it light without burning. I want to install 2 blue LEDs, one on each door behind the lock and I plan to take power from the courtesy light. But After the current leaves the courtesy light and before it reaches the LED...I need to lower the current. I think I need a resisitor but I dont know specificly which one. If anyone has done this before let me know what I need to do. Thanks 6gcers
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![]() Enthusiast ![]() ![]() ![]() ![]() ![]() Joined Feb 3, '06 From Czech Republic (Europe) Currently Offline Reputation: 56 (100%) ![]() |
Any body have any idea how or what I should use to make a 6volt LED light on a 12volt power supply? I know that if I tap it on directly to the 12volt it will burn but I cant figure out how to make it light without burning. I want to install 2 blue LEDs, one on each door behind the lock and I plan to take power from the courtesy light. But After the current leaves the courtesy light and before it reaches the LED...I need to lower the current. I think I need a resisitor but I dont know specificly which one. If anyone has done this before let me know what I need to do. Thanks 6gcers what you need is "burn" 6V somewhere... there are two options how to do that: a) use two 6V LEDs (they share with 12V together and not burn) b) use resistor that will "burn" 6V. Resistor value you calculate from this: R = 6 / I (I is current in Amperes with that LED works with) -------------------- No more replicas... This is evolution... This is SS-four :)
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Lo-Fi Version | Time is now: September 10th, 2025 - 11:17 AM |